2[5z-5(2z-3)]=4z-12

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Solution for 2[5z-5(2z-3)]=4z-12 equation:


Simplifying
2[5z + -5(2z + -3)] = 4z + -12

Reorder the terms:
2[5z + -5(-3 + 2z)] = 4z + -12
2[5z + (-3 * -5 + 2z * -5)] = 4z + -12
2[5z + (15 + -10z)] = 4z + -12

Reorder the terms:
2[15 + 5z + -10z] = 4z + -12

Combine like terms: 5z + -10z = -5z
2[15 + -5z] = 4z + -12
[15 * 2 + -5z * 2] = 4z + -12
[30 + -10z] = 4z + -12

Reorder the terms:
30 + -10z = -12 + 4z

Solving
30 + -10z = -12 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
30 + -10z + -4z = -12 + 4z + -4z

Combine like terms: -10z + -4z = -14z
30 + -14z = -12 + 4z + -4z

Combine like terms: 4z + -4z = 0
30 + -14z = -12 + 0
30 + -14z = -12

Add '-30' to each side of the equation.
30 + -30 + -14z = -12 + -30

Combine like terms: 30 + -30 = 0
0 + -14z = -12 + -30
-14z = -12 + -30

Combine like terms: -12 + -30 = -42
-14z = -42

Divide each side by '-14'.
z = 3

Simplifying
z = 3

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